How can I retrieve a node based on its name using dom4j?

To locate a node based on its node name, you can use an XPath expression. This functionality can be easily implemented using the dom4j library. Here is an example code:

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.Node;
import org.dom4j.XPath;
import org.dom4j.io.SAXReader;

import java.util.List;

public class Dom4jExample {

    public static void main(String[] args) {
        try {
            SAXReader reader = new SAXReader();
            Document document = reader.read("example.xml");

            String nodeName = "book"; // 要获取的节点名称

            // 使用XPath表达式定位节点
            XPath xPath = document.createXPath("//" + nodeName);
            List<Node> nodes = xPath.selectNodes(document);

            for (Node node : nodes) {
                Element element = (Element) node;
                System.out.println(element.asXML()); // 输出节点内容
            }
        } catch (DocumentException e) {
            e.printStackTrace();
        }
    }
}

In the example above, we start by creating a SAXReader object to read an XML file, then use an XPath expression (“//” + nodeName) to locate all nodes with the name “book” and print their content. You can adjust the node name and XML file path as needed.