How to resolve Java array index out of bounds exception?

In Java, an array index out of bounds exception refers to accessing an array with an index beyond the array boundaries. To resolve this exception, you can take the following actions:

1. Ensure the validity of array indices: Before using array indices, make sure that the value of the index is within the valid range. The valid index range for an array is from 0 to the length of the array minus 1. You can use conditional statements (such as if statements) to check if the index is valid, and if it is not, then do not perform the array access operation.
2. To loop through an array: When looping through an array, make sure the value of the loop variable stays within the valid index range. You can use either a for loop or a while loop, and add a check for index validity in the loop condition.
3. Utilize exception handling: If it is not possible to check the validity of an index beforehand through coding, one can use exception handling to deal with array index out of bounds exceptions. Use a try-catch statement block to catch the array index out of bounds exception and handle it within the catch block.

For example, the following code demonstrates how to use exception handling to handle array index out of bounds.

try {
    int[] array = {1, 2, 3};
    int value = array[3]; // 越界访问
} catch (ArrayIndexOutOfBoundsException e) {
    System.out.println("数组下标越界异常");
    e.printStackTrace();
    // 其他处理逻辑
}

In the code above, an attempt to access the element at index 3 is made, but the array only has a length of 3, which will result in an array index out of bounds exception. In the catch block, the exception message can be printed or other handling logic can be executed.